S. D. V. Stephens

notes / Studies in Algebra and Group Theory / chapter 1: Sets and Groups

4 Lagrange’s Theorem, Normal Subgroups and Quotients

· Denis Auroux

Original Professor Auroux’s handwritten notes (PDF), behind a password for now:

Cosets (recap)

Last time we discussed equivalence relations.

Definition 4.1 (Cosets). Given a subgroup of a group :

  • is called the (left) coset of containing .
  • The relation is an equivalence relation on , whose equivalence classes are the left cosets.
  • The quotient (the set of left cosets) is denoted by . We have a partition

Proof.

  • , so for all .
  • If , then , hence , hence .
  • If and , then and , so , i.e. .

Also, such that such that . ∎

Example 4.2. The cosets of are = congruence classes mod (). So

Lagrange’s theorem

Definition 4.3. The index of the subgroup is the number of cosets, .

When is a finite group, since each coset has (bijection , ), the partition implies

Theorem 4.4 (Lagrange’s theorem).

Corollary 4.5. If is a subgroup of a finite group , then divides .

Corollary 4.6. For all a finite group, the order of divides .

(Recall the order of is the smallest such that , and also the order of the subgroup .)

Corollary 4.7. If is prime, then .

(Indeed, take such that ; then has order , hence , , and by mapping .)

Quotient groups

In the case of , the equivalence relation is compatible with addition, so inherits a group structure, given by addition of cosets: (the same coset no matter how we choose within their cosets).

In general, trying to define a group structure on by setting might not work. The obstacle to this is: assume () and (). Does it follow that ()? If not, our operation isn’t well defined.

This works fine whenever is the kernel of a homomorphism. Let be a homomorphism with . Recall Now, if and , then , so ✓. We can define multiplication of cosets by .

In fact, we have a bijection and this bijection is a group isomorphism! (Because .)

But it fails for general subgroups.

Example 4.8. = symmetries of the square, where = horizontal flip. Then (the coset ). But setting = rotation by , is the reflection across one diagonal, while the coset of is , where is the reflection across the other diagonal.

Four squares illustrating symmetries of the square: h, the flip across the vertical axis; r, rotation by 90 degrees; h∘r, the reflection across the diagonal from bottom left to top right; and r∘h, the reflection across the other diagonal.

So , even though (and ).

Normal subgroups

Right cosets vs. left cosets: similarly to the left cosets (), we define right cosets , which correspond to .

Remark. None of these are subgroups of (except for itself)! (They don’t contain !)

Also denote (this one is a subgroup).

Definition 4.9. is a normal subgroup if , (“left cosets = right cosets”; this means the two equivalence relations above agree), or equivalently, , ( is closed under conjugation by elements of ).

Example 4.10.

  • Any subgroup of an abelian group is normal ( ✓).
  • In , the subgroup ( = horizontal reflection) is not normal: .

Theorem 4.11. Given a group and a subgroup , the following are equivalent:

  1. there exists a group homomorphism (some other group) with ;
  2. is a normal subgroup;
  3. has a group structure given by .

Proof. (1) ⇒ (2). Suppose there exists a homomorphism with . Then for all , but also So for all : is normal.

(2) ⇒ (3). Assume is normal, and define an operation on by .

  • We need to check that this is well-defined, i.e. and . Equivalently: , . Using that is normal, , so
  • It clearly satisfies the group axioms: ; similarly the other axioms follow from the definition of the operation and the fact that is a group.

(3) ⇒ (1). Now, , is clearly a homomorphism with kernel . ∎

Remark. If is a group homomorphism, then is a normal subgroup, and factors as where is an isomorphism, as seen above. Hence (with the isomorphism given by ).

Example:

= permutations of = symmetries of the triangle

An equilateral triangle with its centre marked and vertices labelled 1 at bottom left, 2 at bottom right and 3 at the top.

It contains:

  • = identity, which does nothing; order 1.
  • three transpositions, which swap two elements: , , reflections of the triangle; order 2.
  • two 3-cycles, and rotations by . These have order 3.

(Cycle notation: means .)

Subgroups of . They have order 1, 2, 3 or 6 (and those of order 2 or 3 are necessarily cyclic):

  • , trivial;
  • and two others ();
  • , the subgroup of rotations ();
  • all of .

and are obviously normal subgroups.

is not normal: its conjugate is (rotate clockwise, then swap , then rotate counterclockwise swap ).

is normal. It’s the kernel of

Notes not reached in this lecture, covered at the start of {{LINK:L05}}

Definition 4.12. Say a group is simple if it has no normal subgroups other than and .

We use normal subgroups to view as built from hopefully simpler groups and . Simple groups are then the basic building blocks.

Exact sequences

Definition 4.13. A sequence of groups and homomorphisms is an exact sequence if , .

This means such that . In particular, = the trivial homomorphism ( for all ) ().

A short exact sequence is the simplest case, ( is often denoted for multiplicative groups, for additive ones). This means:

  • is an injective homomorphism;
  • is a surjective homomorphism;
  • .

Proposition 4.14. Such an exact sequence exists iff contains a normal subgroup isomorphic to and such that the quotient group is isomorphic to .

(The prototype short exact sequence is .)

Example 4.15. For any groups and ,

Example 4.16. and

Example 4.17. There exists an exact sequence but not (there is no normal subgroup of order 2!).