S. D. V. Stephens

notes / Studies in Algebra and Group Theory / chapter 5: Multilinear Algebra / From my book

B9.9 Multilinear Maps and the Tensor Algebra

9.9.1 Multilinear Maps

The constructions of the previous section extend from two factors to any finite number of them.

Definition 9.9.1 (Multilinear map). Let and be vector spaces over . A map is multilinear (or -linear) if it is linear in each variable when the others are held fixed. When , is a multilinear form.

Theorem 9.9.2 (Tensor product of several spaces). Let be finite-dimensional, and let be a basis of . There is a vector space together with a multilinear map such that for every vector space and every multilinear map there is a unique linear map with . It is unique up to unique isomorphism, the pure tensors with form a basis of it, and .

Proof. This is the proof of Theorem 9.8.6 with more indices. Let be the vector space with basis the symbols (). If , set which is multilinear. Given , the linear map with satisfies , by expanding using multilinearity; and it is the only linear map that can, since its values on a basis are forced. Uniqueness up to unique isomorphism is proved exactly as in Theorem 9.8.6(iii). ∎

As before, the space can also be built as a quotient of the vector space with basis all symbols , by the relations expressing multilinearity. Linear maps induce a linear map with , since the right side is multilinear in the ; exactly as in Proposition 9.8.7, this construction is compatible with composition and identities.

Proposition 9.9.3 (Associativity). For finite-dimensional vector spaces and , there is an isomorphism with . In particular .

Proof. The map is multilinear: it is linear in because is linear in and is linear in its first argument, and similarly for each . By Theorem 9.9.2 it induces a linear map with the stated values. Choose bases of all the spaces. Then sends the basis tensor to . The tensors form a basis of , and similarly for the ’s, so by Theorem 9.8.6 these images form a basis of the target. So sends a basis to a basis. ∎

Thus nothing new happens with more than two factors, and we may drop parentheses in iterated tensor products.

9.9.2 Tensor Powers and the Tensor Algebra

Definition 9.9.4 (Tensor powers). For a vector space and , the th tensor power of is By convention, and . If , then . For a linear map we write .

By Proposition 9.9.3, . Composing this isomorphism with the bilinear map gives a bilinear multiplication , which is concatenation of tensors. When or it is multiplication by a scalar.

Definition 9.9.5 (Tensor algebra). The tensor algebra of is the direct sum whose elements are finite sums with , with the multiplication that extends the products bilinearly.

Note. is a ring: the multiplication distributes over addition because it is bilinear, it has the identity , and it is associative because and are trilinear in and agree on pure tensors, where both are concatenation. It is also a vector space over whose multiplication is bilinear; a ring with this extra structure is called a -algebra. The tensor algebra is graded: it is the direct sum of the subspaces , and . It is not commutative once : for linearly independent , the tensors and are distinct elements of a basis of . As a vector space, is infinite-dimensional unless .

The tensor algebra is the free -algebra on : every linear map into a -algebra extends uniquely to a -linear ring homomorphism with , namely . This formula defines on each , because the right side is multilinear in the ; is multiplicative because and are bilinear in and agree on pure tensors; and is unique because is spanned by and the products of elements of .

Proposition 9.9.6 (Multilinear forms). For finite-dimensional vector spaces there are isomorphisms under which corresponds to the form . In particular is the space of -linear forms on .

Proof. The second isomorphism is the universal property: is a linear bijection from multilinear forms to linear functionals on . For the first, argue as in Proposition 9.8.13(i): the form depends multilinearly on , so it induces a linear map , and this map sends the tensor product of dual basis vectors to the functional that is on and on the other basis tensors. So it sends a basis to the dual basis. ∎